SAT Math Bible by Jeff Kolby

By Jeff Kolby

Finished Prep for SAT Math
Every 12 months, scholars pay $1,000 and extra to check prep businesses to organize for the mathematics portion of the SAT. you can now get an analogous practise in a book.
Although the SAT math part is hard, it's very learnable. SAT Math Bible provides an intensive research of SAT math and introduces quite a few analytic innovations that can assist you immensely, not just at the SAT yet in collage besides. Features:
Comprehensive evaluate: Twenty-three chapters give you the such a lot thorough evaluate of SAT math available.
Practice: contains 164 examples and greater than 500 workouts! prepared from effortless to medium to not easy to very hard.
Diagnostic try: The diagnostic attempt measures your strengths and weaknesses and directs you to parts you want to examine more.
Duals: those are pairs of comparable difficulties during which just one estate is assorted. They illustrate the method of making SAT questions.

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Extra resources for SAT Math Bible

Sample text

A) 5 (B) 7 (C) 43 (D) 57 (E) 570 Since the remainder is 57 when the number is divided by 10,000, the number can be expressed as 10,000n + 57, where n is an integer. Rewriting 10,000 as 1,000(10) yields 1,000(10)n + 57 = 1,000(10n) + 57 = Now, since n is an integer, 10n is an integer. Letting 10n = q, we get 1,000q + 57 = Hence, the remainder is still 57 (by the p = kq + r form) when the number is divided by 1,000. The answer is (D). Method II (Alternative form) Since the remainder is 57 when the number is divided by 10,000, the number can be expressed as 10,000n + 57.

Hence, total number of ways of forming the three-digit number equals 3 × 4 × 4 = 48. Hence, the total number of ways of forming the number is 4 + 16 + 48 = 68. The answer is (D). 47 Geometry About one-fourth of the math problems on the SAT involve geometry. ) Fortunately, the figures on the SAT are usually drawn to scale. Hence, you can check your work and in some cases even solve a problem by “eyeballing” the drawing. We’ll discuss this technique in detail later. Following is a discussion of the basic properties of geometry.

Reject. If q ≥ 49, p ≤ 46 – 49 = –3, not positive either. Reject. So, we have only one acceptable assumption and that is n = 3 and therefore m = 5. Hence, mn = 3 ⋅ 5 = 15. The answer is (A). 27. We are given that x = 2 ⋅ 3 ⋅ 7 ⋅ a = 42a and y = 2 ⋅ 2 ⋅ 8 ⋅ b = 32b. We are given that the values of both x and y lie between 120 and 130 (not including the two). The only multiple of 42 in this range is 42 × 3 = 126. Hence, x = 126 and a = 3. The only multiple of 32 in this range is 32 × 4 = 128. Hence, y = 128 and b = 4.

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